0=4n^2+64n

Solution for 0=4n^2+64n equation:

0=4n^2+64n

We move all terms to the left:

0-(4n^2+64n)=0

We add all the numbers together, and all the variables

-(4n^2+64n)=0

We get rid of parentheses

-4n^2-64n=0

a = -4; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·(-4)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*-4}=\frac{0}{-8}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*-4}=\frac{128}{-8}
=-16
$